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OPERATING MANUAL
PERFORMANCE
TAKEOFF
TAKEOFF CHARTS - MTOW CALCULATION (WEIGHT ENTRY)
A330/A340 FLEET PER-TOF-TOC-18-10 P 8/12
FCOM 19 AUG 10
• ApplyWET correction
For􀀃OAT􀀃<􀀃TVMC􀀃(57􀀃°),􀀃ΔW􀀃=.................................................................................................0.0􀀃
Intermediate weight (1 000 kg)..............................................................................................215.1
Associated speeds,
V1 = 150 kt - 0 = 150 kt
VR = 151 kt - 0 = 151 kt
V2 = 156 kt - 0 = 156 kt
(No speed check required for first correction)
• Apply QNH correction
For􀀃OAT􀀃<􀀃TVMC􀀃(54􀀃°),􀀃ΔW􀀃=􀀃-􀀃2.2􀀃×􀀃15/10􀀃=......................................................................-􀀃3.3􀀃
Maximum permissible takeoff weight (1 000 kg)................................................................... 211.8
Associated speeds,
V1 = 150 kt - 1 × 15/10 = 148 kt
VR = 151 kt - 1 × 15/10 = 150 kt
V2 = 156 kt - 1 × 15/10 = 155 kt
• Check that the speeds are higher than minimum speeds from the chart and from VMU table.
Takeoff Configuration : 1 + F
TOWV1 VR V2
TOW(RTOW) 215.1 150 151 156
FCOM correction(s)
Intermediate value 215.1 150 151 156
WET Correction 0.0 0 0 0
Intermediate value 215.1 150 151 156
QNH Correction - 3.3 -2 -1 -1
Final value 211.8 148 150 155
COMBINING CORRECTIONS FROM FCOM AND CHART
Applicable to:
Proceed as follows :
1. Determine the maximum takeoff weight by entering the chart with selected configuration, OAT and
wind.
2. Apply corrections from FCOM to determine an intermediate weight. Interpolate associated speeds
for intermediate weight in the same column (same wind and configuration).
3. Apply corrections from RTOW chart as explained above.
A330/A340 FLIGHT CREW
OPERATING MANUAL
PERFORMANCE
TAKEOFF
TAKEOFF CHARTS - MTOW CALCULATION (WEIGHT ENTRY)
A330/A340 FLEET PER-TOF-TOC-18-10 P 9/12
FCOM 19 AUG 10
EXAMPLE C
DATA: OAT = 25 °C
Head wind = 10 kt
Air conditioning ON
QNH = 998 hPa
WET runway
1. Use the chart (Refer to PER-TOF-TOC-16-30 CHART LAYOUT).
Enter the 10 kt head wind column, CONF 1+F, to read for 25 °C
Max TO weight (1 000 kg) air conditioning OFF = 270.3 + 1.65 × 4 + 0.16 × 5 = 277.7
Enter the 10 kt head wind column CONF 2, to read for 25 °C
Max TO weight (1 000 kg) air conditioning OFF = 272.0 + 1.64 × 2 + 0.14 × 5 = 276.0
Retain CONF 1+F for takeoff configuration.
2. First, apply the correction (Refer to PER-TOF-TOD-24 EFFECT OF QNH AND BLEEDS).
Max TO weight (1 000 kg) air conditioning OFF................................................................... 277.7
Air conditioning correction..................................................................................................... - 17.5
Intermediate weight................................................................................................................260.2
Interpolate takeoff speeds for 260.2 (1 000 kg) in the 10 kt head wind column,
V1 = 152 kt , VR = 161 kt , V2 = 167 kt
3. ApplyWET correction
For􀀃OAT􀀃<􀀃TVMC􀀃(54􀀃°),􀀃ΔW􀀃=..............................................................................................􀀃-􀀃0.1􀀃
Intermediate weight................................................................................................................260.1
Associated speeds,
V1 = 152 kt - 2 = 150 kt
VR = 161 kt - 0 = 161 kt
V2 = 167 kt - 0 = 167 kt
Check that the speeds are higher than minimum speeds from the chart and from VMU table.
Apply QNH correction
For􀀃OAT􀀃<􀀃TVMC􀀃(54􀀃°),􀀃ΔW􀀃=􀀃2.7􀀃×􀀃15/10􀀃=........................................................................-􀀃4.1􀀃
Maximum permissible takeoff weight.....................................................................................256.0
Associated speed,
V1 = 150 kt - 1 × 15/10 = 148 kt
VR = 161 kt - 1 × 15/10 = 160 kt
V2 = 167 kt - 1 × 15/10 = 166 kt
Check that the speeds are higher than minimum speeds from the chart and from VMU table. (It
is reminded that if the speed checks are not fulfilled, the corrections must be recalculated using
those provided on lines 3 and 4).
　
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