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V2 = 157 kt + 1 × 15/10 = 159 kt
Check that the speeds are higher than minimum speeds from the chart and from VMU table. (It
is reminded that if the speed checks are not fulfilled, the corrections must be recalculated using
those provided on lines 3 and 4).
Since the speed check is fulfilled :
Maximum permissible takeoff weight = 79.0 (1 000 kg)
V1 = 143 kt, VR = 154 kt, V2 = 159 kt.
Takeoff Configuration : 2
TOW V1 VR V2
TOW (RTOW) 82.1
FCOM correction(s) - 2.2
Intermediate value 79.9 152 153 158
WET Correction - 1.2 -10 -1 -1
Intermediate value 78.7 142 152 157
QNH Correction + 0.3 +1 +2 +2
Final value 79.0 143 154 159
COMBINING CORRECTIONS FROM FCOM AND CHART
Applicable to: MSN,
Proceed as follows :
1. Enter the chart with selected configuration, OAT and wind to read the maximum takeoff weight.
2. Apply corrections from FCOM to determine an intermediate weight. Interpolate associated speeds
for intermediate weight in the same column (same wind and configuration).
3. Apply corrections from RTOW chart as explained above.
EXAMPLE 3
DATA :: OAT = 25 °C
Head wind = 10 kt
Air conditioning ON
QNH = 1 028 hPa
WET runway
1. Use the chart (Refer to DSC-45-25 GENERAL).
Enter the 10 kt head wind column and interpolate for 25 °C, CONF 1+F,
Max TO weight (1 000 kg) air conditioning OFF..................................................................... 82.1
Enter the 10 kt head wind column and interpolate for 25 °C, CONF 2,
A318/A319/A320/A321 FLIGHT CREW
OPERATING MANUAL
PERFORMANCE
TAKEOFF
TAKEOFF CHARTS - MTOW CALCULATION (TEMPERATURE ENTRY)
A318/A319/A320/A321 FLEET PER-TOF-TOC-12-10 P 22/22
FCOM 19 AUG 10
Max TO weight (1 000 kg) air conditioning OFF..................................................................... 82.1
Retain CONF 2 for takeoff configuration as the speeds are lower.
2. First, apply the correction (Refer to DSC-52-30 WARNINGS AND CAUTIONS).
Max TO weight (1 000 kg) air conditioning OFF..................................................................... 82.1
Air conditioning correction.......................................................................................................- 1.8
Intermediate weight..................................................................................................................80.3
Interpolate takeoff speeds for 80.3 (1 000 kg) in the 10 kt head wind column,
V1 = 152 kt , VR = 153 kt , V2 = 158 kt
3. Apply WET correction
Enq􀀃N􀀤S􀀃􀀟􀀃SULB􀀃􀀋43􀀃°B(+􀀃ΔV􀀃<􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑􀀑- 1.2
Intermediate weight..................................................................................................................79.1
Associated speeds,
V1 = 152 kt - 10 = 142 kt
VR = 153 kt - 1 = 152 kt
V2 = 158 kt - 1 = 157 kt
Check that the speeds are higher than minimum speeds from the chart and from VMU table
Apply QNH correction
Enq􀀃N􀀤S􀀃􀀟􀀃SULB􀀃􀀋43􀀃°B(+􀀃ΔV􀀃<􀀃/􀀑1􀀃×􀀃04.0/􀀃<􀀑􀀑􀀑..................................................................+ 0.3
Maximum permissible takeoff weight.......................................................................................79.4
Associated speed,
V1 = 142 kt + 1 × 15/10 = 143 kt
VR = 152 kt + 1 × 15/10 = 154 kt
V2 = 157 kt + 1 × 15/10 = 159 kt
Check that the speeds are higher than minimum speeds from the chart and from VMU table. (It
is reminded that if the speed checks are not fulfilled, the corrections must be recalculated using
those provided on lines 3 and 4).
Since the speed check is fulfilled :
　
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